Physics, asked by akahu2, 1 year ago

a farmer moves along the boundary of a square field of side 10m in 40s. what will be the magnitude of displacement of the farmer at the end of 2 minutes 20 second from his initial position?

Answers

Answered by RajSharmaa
1
answer for this can be taken from any reference book....answer is 14.14.....hopde it helps

manavmore32Raghav: He doesn't know the exact solution actually
RajSharmaa: no
RajSharmaa: i know
RajSharmaa: see....
RajSharmaa: boundary of side 10 m means perimeter is 40 metre...now make a table having time.....distance displacement.....
RajSharmaa: in 40 sec dist is 40 ....disp is zero......in next 40 distance 80 and displacement is again zero
RajSharmaa: nd 2 min 20 sec means 140 sec....
RajSharmaa: so like this......when you complete the table displacement is the diagonal...and then using pythagoras theorem you get 10✓2 means 14.14
RajSharmaa: and yes manavmore32 raghav......you dont actually knew the answer....
RajSharmaa: know
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