Question

A farmer moves along the boundary of a square field of side 10 m in 40 s what will be the magnitude of displacement of the farmer at the end of 2minutes

Answer 1

Explanation:

In 40 sec ------ 10m

In 1 sec -------- 10/40 = 1/4 m

therefore,

120 sec =

$\frac{1}{4} \times 120$

$= 30 \: m$

Answer 2

Answer:

Here is the answer

Explanation:

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