Physics, asked by anupam2331992, 10 months ago

a farmer moves along the boundary of a square field of side 10 m in 40 seconds the magnitude of displacement of the farmer at the end of 2 minutes and 22nd is​

Answers

Answered by devasheeshrana1412
0

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Time= 2min 22 sec= 142sec

Time taken to complete perimeter of square=40 sec

So, after 120 sec, he would be at the starting point.

Speed = distance/time

Speed=4×10/40

Speed = 1m/s

After 22 sec, his displacement would be,

Displacement ²=8²+10²

Displacement ²=64+100

Displacement=√164

Displacement=12.8m

Hope it helps.

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