Question

A farmer moves along the boundary of a square field of side 10 m in 40 s. What will be the magnitude of displacement of the far mer at the end of 2 minutes 20 seconds from his initial position?

Answer 1

$\tt\it\bf\it\large\bm{\mathcal{\fcolorbox{blue}{white}{\blue{Given:-}}}}$

➠ side of square = 10m

➠ time taken to cover the boundary= 40s

$\tt\it\bf\it\large\bm{\mathcal{\fcolorbox{blue}{white}{\green{Solution:-}}}}$

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In 40 sec it cover 10m to come in it's initial position.

so,

In 1 sec it cover = 10/40 = 1/4m

In 2 min 20 sec (2x60 + 20) =140 sec, it will cover

distance = 140 x 1/4 = 35m.

let, the displacement be d:-

d²= 10²+5²

d²=100+25

d²=125

d=√125 =√5x5x5

or,

d=25√5m

Hence, displacement is 25√5 m

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