A farmer moves along the boundary of a square field of side
10 m in 40 s. What will be the magnitude of displacement of the
farmer at the end of 2 minutes 20 seconds from his initial position?
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Answer:
Total distance covered 10m in 40sec
Total time taken= 2min 20sec= 140sec
Total round completed = 140/40=3.5 rounds
So If an object moves from A to D, the shortest path will be from A to C. So displacement is AC, that we will find by phythogoras theorem.
AC2= AB2 +BC2
AC2= (10)2 +(10)2
AC2= 100+100
AC2=200
AC = (200)1/2
AC= 10× (2) ½
Hope it helps......
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