Math, asked by ashokyadav15101973, 9 months ago

A farmer moves along the boundary of a square field of side 10 m in 40 s. what is be the magnitude of
displacement of the farmer at the end of 2 minutes 20 seconds?

Answers

Answered by kumarabhishek5
3

Answer:

10√2

Step-by-step explanation:

because in 2mintue 40 second he covered 7/2 round displacement is short distance between two points so 10×10+10×10= displacement× displacement so 200= displacement square so √200=10√2

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