Question

A farmer moves along the boundary of a square field of side 10 m in 40 sec. The magnitude of
displacement of the farmer at the end of 2 minutes 20 seconds from his initial position is
a. 10m b. 30m c. 40m d. 10√2m

Answer 1

Answer:

displacement of the farmer = 10√2 m

Explanation:

given the length of side the square feild

= 10 m

A farmer moves along the boundry in 40 s

perimeter of the feild = 4 × side

4 × 10

perimeter = 40 m

now given

farmer moves for 2 minutes 20 seconds

= 140 seconds

he will move around boundary =

140

= 120 + 20

(40 ×3) + 20

= 3 rounds

and moves more for 20 seconds

distance moved in 20 seconds

= 40/2 m

= 20 m

= two adjescent sides of the feild

so,

displacement = diagonal of the square feild

diagonal = √(10² + 10²)

= √(100 + 100)

= √200

= 10√2 m

so,

displacement of the farmer = 10√2 m

Answer 2

Answer:

30cm is ur answer buddy

Step-by-step explanation:

ok aa broo