Question

a farmer moves along the boundary of a square field of side 10 m in 40 s.whar will be the magnitude of displacement of the farmer at the end of 2 mins 20 secs from his initial point​

Answer 1

Answer:

Explanation:

Distance time

10m 40s

x 2*60+20=140s

x=10*140/40=35m

Distance =10+10+10+5

Side=10m

So displacement = 5m

Refer to attachment

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