Question

A farmer moves along the
boundary of a square field of side
10 m in 40 s. What will be the
magnitude of displacement of the
farmer at the end of 2 minutes 20
seconds from his initial position?​

Answer 1

Answer:

Explanation:

A farmer moves along the boundary of a square field of side 10 m in 40 s. What will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position? Farmer takes 40 s to move along the boundary. Thus, after 3.5Side of the square = 10 m

Perimeter of the square = 4×10 = 40 m

He completes 1 round in 40 s.

So, speed = 40/40 = 1 m/s

So, distance covered in 2 min 20 s or 140 s is = 140 × 1 = 140 m

Number of rounds of the square completed in moving through 140 m is = 140/40 = 3.5

In 3 rounds the displacement is zero. In 0.5 round the farmer reaches the diagonally opposite end of the square from his starting point.

Displacement = AC = (AB2 + BC2)1/2 = (100+100)1/2 = 10?2 m round farmer will at point C of the field.

Answer 2

Explanation:

by seeing the question we can say 55 m

I hope I helped you