Question

A farmer moves along the boundary of a square field of side 10 m in 40 s. What will be the magnitude of displacement of the farmer at the end of 2 minutes 20seconds from his initial position?​

Answer 1

Explanation:

Given side of square =10m, thus perimeter P=40m

Time taken to cover the boundary of 40 m =40 s

Thus in 1 second, the farmer covers a distance of 1 m

Now distance covered by the farmer in 2 min 20 seconds = 1×140=140m

Now the total number of rotation the farmer makes to cover a distance of 140 meters =perimetertotaldistance

=3.5 

At this point, the farmer is at a point say B from the origin O

Thus the displacement s=10ka sqaure+10 ka sqaure from Pythagoras theorem.

s=10root2=14.14m