Question

A farmer moves along the boundary of a square field of side 20 m in 60 s. What will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position?

Answer 1

Answer:

21.08 m

Explanation:

Farmer reaches his initial position after every 60 seconds. After 2 minutes, he's back to his initial position. Now, we need to check his position after 20 seconds.

Time taken for each side (20 m) = 15 seconds

For the remaining 5 seconds, distance covered = (20/15) x 5 = 20/3 m

Imagine a right triangle of base 20 m and height 20/3 m. The hypotenuse of that triangle is the displacement.

$\sqrt{ {20}^{2} + {( \frac{20}{3}) }^{2} }$