Question

A Farmer moves along the boundary of a Square field of side 10 m in

42s. What will be the magnitude of displacement of the farmer at

the end of 2 m 22 s from his initial position?​

Answer 1

$\rule{200}{2}$

ANSWER:

• Magnitude of displacement of the farmer = 25.23 m

$\rule{200}{2}$

GIVEN:

• A Farmer moves along the boundary of a Square field of side 10 m

• Time taken for coming back again to the initial position = 42 s

• He walked for 2 min 22 s

$\rule{200}{2}$

TO FIND:

• Magnitude of displacement of the farmer

$\rule{200}{2}$

CONVERSIONS:

• 1 minute = 60 s

• 2 minutes 22 s = 120 + 22 = 142 s

$\rule{200}{2}$

EXPLANATION:

PERIMETER OF THE SQUARE = 4a

Perimeter of the field = 4(10) = 40 m

For 42 s →→→→→→→→→→ 40 m

For 142 s →→→→→→→→→→ x m

x = (142 × 40) / 42

x = (20 × 142) / 21

x = 2840 / 21

x = 135.23 m

For completing the square 3 times he would travel 3 × 40 m = 120 m

135.23 - 120 = 25.23 m

The farmer should have started the fourth round and completed a displacement of 25.23 m.

Hence the displacement of the farmer = 25.23 m

$\rule{200}{2}$