A farmer moves along the boundary of a square field of side 10 metre in 40 seconds. What will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position ?
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Answered by
4
Answer:
Hi friend,
Total distance covered 10m in 40sec
Total time taken= 2min 20sec= 140sec
Total round completed = 140/40=3.5 rounds
So If an object moves from A to D, the shortest path will be from A to C. So displacement is AC, that we will find by phythogoras theorem.
AC2= AB2 +BC2
AC2= (10)2 +(10)2
AC2= 100+100
AC2=200
AC = (200)1/2
AC= 10× (2) ½
Hope it helps......
Explanation:
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Answered by
1
Answer:
Farmer takes 40 s to move along the boundary. Thus, after 3.5 round farmer will at point C of the field. Thus, after 2 min 20 seconds the displacement of farmer will be equal to 14.14 m north east from initial position.
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