Physics, asked by priya471sharma471, 8 months ago

A farmer moves along the boundary of a square field of side 10 metre in 40 seconds. What will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position ?​

Answers

Answered by aditikgupta01
4

Answer:

Hi friend,

Total distance covered 10m in 40sec

Total time taken= 2min 20sec= 140sec

Total round completed = 140/40=3.5 rounds

So If an object moves from A to D, the shortest path will be from A to C. So displacement is AC, that we will find by phythogoras theorem.

AC2= AB2 +BC2  

AC2= (10)2 +(10)2

AC2= 100+100

AC2=200

AC = (200)1/2

 

AC= 10× (2) ½  

Hope it helps......

Explanation:

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Answered by ankajvaish2016
1

Answer:

Farmer takes 40 s to move along the boundary. Thus, after 3.5 round farmer will at point C of the field. Thus, after 2 min 20 seconds the displacement of farmer will be equal to 14.14 m north east from initial position.

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