Question

a farmer moves along the boundary of a square field of side 10 m in 40 seconds what will be the magnitude of displacement of the form at the end of 2 minutes 20 seconds

Answer 1

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Syeda answered 9 month(s) ago
a farmer moves along the boundary of a square field of side 10 m in 40 seconds.what will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position?
a farmer moves along the boundary of a square field of side 10m in 40s.what will be the magnitude of displacement of the farmer at the end of 2minutes 20s from his initial position?


person
Asked by Mohammed

May 21

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8 Answers
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person
Amarnathreddy , SubjectMatterExpert

Member since Jul 09 2013


Answer:
Total distance 40m in 40 sec.
Total time taken by the farmer = 2 min 20 sec. =140 seconds.
Total rounds completed= 140/40=3.5 rounds
That means if the farmer starts from point A of the square field, he reaches point C.
Therefore, displacement is AC.
Assume ABC is a right angled triangle.
Therefore,
AC2= AB2 +BC2
AC2= (10)2 +(10)2
AC2= 100+100
AC2=200

AC = (200)1/2

AC= 10× (2) ½