a farmer moves along the boundary of a square field of side 10m in 40secs .what will be the magnitude of displacement of the farmer at the end of 2mins 20secs from his initial position?
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The perimeter of the square field is 40 m.
He took 40 seconds which means his speed is 1 m per second.
2 minutes 20 seconds = 140 seconds.
Speed * time = distance.
Distance covered = 140 metres.
If he starts from one corner of field after 3 rounds he travels 120 metres.
Remaining 20 metres , he gets to the opposite corner.
Therefore displacement = length of diagonal of square.
Using Pythagoras theorem
Diagonal = root(10² + 10²)
= root 200 = 10 root 2 metres.
The displacement is 10 * 1.414 = 14.14 metres.
Note: We have taken root 2 as 1.414 up to 3 decimal places.
Hope it helps.....
Any doubts , comment down or message me.
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- Mâhêshwáràñ.
He took 40 seconds which means his speed is 1 m per second.
2 minutes 20 seconds = 140 seconds.
Speed * time = distance.
Distance covered = 140 metres.
If he starts from one corner of field after 3 rounds he travels 120 metres.
Remaining 20 metres , he gets to the opposite corner.
Therefore displacement = length of diagonal of square.
Using Pythagoras theorem
Diagonal = root(10² + 10²)
= root 200 = 10 root 2 metres.
The displacement is 10 * 1.414 = 14.14 metres.
Note: We have taken root 2 as 1.414 up to 3 decimal places.
Hope it helps.....
Any doubts , comment down or message me.
Mark my answer as brainliest if it helped.
- Mâhêshwáràñ.
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