A farmer moves along the boundary of a square field of side 10 m in 40s. what will be the magnitude of its displacement of the farmer at the end of 2minutes 20 seconds.
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farmer speed is 4*10/40 m/sec=1m/sec
in 2min 20 sec i.e 140 sec he moves 140 m.
every after 40m his disp. is zero.
now for remaining 20m (140-3*40) he will be diagonally opposite point, assuming he starts from corner point.
hence displ. shall be 10√2.
in 2min 20 sec i.e 140 sec he moves 140 m.
every after 40m his disp. is zero.
now for remaining 20m (140-3*40) he will be diagonally opposite point, assuming he starts from corner point.
hence displ. shall be 10√2.
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