Question

A farmer moves along the boundary of a square field of side 10 m in 40 s. What will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position?​

Answer 1

Answer:

Farmer takes 40 s to move along the boundary. Thus, after 3.5 round farmer will at point C of the field. Thus, after 2 min 20 seconds the displacement of farmer will be equal to 14.14 m north east from initial position.

Explanation:

Answer 2

Answer:

Given side of square = 10m, thus

perimeter P = 40m

Time taken to cover the boundary of 40m

=40 s

Thus in 1 second, the farmer covers a

distance of 1m

Now distance covered by the farmer in 2 min 20 seconds =1 x 140 = 140m

Now the total number of rotation the farmer makes to cover a distance of 140

meters

= 3.5

total distance

perimeter

At this point, the farmer is at a point say B from the origin O

Thus the displacements = 102 + 10 from Pythagoras theorem.

s=10/2 = 14.14m