Question

a farmer moves along the boundary of a square field of side 10 m in 40s what will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position

Answer 1

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Answer 2

here is your answer

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rounds completed by farmer are=
(2×60+20)/40 = 140/40 =7/2 rounds
or 3 complete and one half round

displacement of 3 complete round =0m
displacement of 1/2 round= diagonal of field
(because it will cover 2 sides of field and shortest distance is diagonal which is equal to displacement)
= √(100+100) =√200 =10√2m

net displacement =10√2 m

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