a farmer moves along the boundary of a square field of side 10m in 40s.what will be the magnitude of displacement at the end of 2 minute 20 seconds from his initial position?
Answers
Answered by
3
At first...
We convert time from min to sec....
We know that it takes 40sec to complete on around i.e. 0 displacement...
No dividing 140 by 40 we get 20 sec as the remainder...
Now we need to find the distance travelled in 20 sec...
Which is 20 m.
Now drawing a square the distance is 20 m but the displacement is diagonal .... i.e 10√2 which is obtained by pythagoras theorem....
Thanks and keep going...
Mark as brainliest....
We convert time from min to sec....
We know that it takes 40sec to complete on around i.e. 0 displacement...
No dividing 140 by 40 we get 20 sec as the remainder...
Now we need to find the distance travelled in 20 sec...
Which is 20 m.
Now drawing a square the distance is 20 m but the displacement is diagonal .... i.e 10√2 which is obtained by pythagoras theorem....
Thanks and keep going...
Mark as brainliest....
Attachments:
Similar questions