Question

A farmer moves along the boundary of a square field of side 10 metre in 40 seconds what will the magnitude of displacement of the Palmer at the end of 2 minute 20 seconds

Answer 1

heyy!!! here's ur ans

given: side of a sq field = 10m
perimeter= 4*10 = 40m
time taken to cover 40m = 40 sec
2min 20sec= 140sec
distance covered in 140sec = 140*40/40
= 140m
no. of rotation = 140/40
= 3.5 rounds
therefore after 3.5 rounds farmers will be at point C
displacement = AC=root(10^2+10^2)[by pythagorean property
= root (2*10^2)
= 10 root 2

hope it'll help

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