a farmer moves along the boundary of a square field of side 10m in 40s. what will be the magnitude of a displacement of the farmer at the end of 2mins 20 sec from his initial position?
Answers
Answered by
7
Answer:
The answer is 14.14.
Explanation:
1 round=40m
T=40s
T=2min 20sec
in sec
=(2×60)+20
=120+20
=140
Total round=140/40
=3.5
Diagonal of sq.=Root 2a
=1.414×10
=14.14m
Similar questions