Physics, asked by meen14garg, 6 hours ago

A farmer moves along the boundary of a square field of side 20 m in 40 s. What will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position?

Answers

Answered by yukhtha2008

Explanation:

14.14 m north east

Farmer takes 40 s to move along the boundary. Thus, after 3.5 round farmer will at point C of the field. Thus, after 2 min 20 seconds the displacement of farmer will be equal to 14.14 m north east from initial position.

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A farmer moves along the boundary of a square field of side 20 m in 40 s. What will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position?​

Answers

A farmer moves along the boundary of a square field of side 20 m in 40 s. What will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position?