a farmer moves along the boundary of a square field of side 10m in 40s. what will be the magnitude of displacement of the farmer at the end of 2 min 20 sec????
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Answered by
2
2 min 20 sec =140 sec
140/40=7/2
7/2 ×10=35
displacement is5 m
140/40=7/2
7/2 ×10=35
displacement is5 m
Answered by
14
Hii there!!
Distance travelled in 40s= 40m
Distance travelled in 2mins 20s=
2*60+20= 140s
>>40/40*140= 140m
See the next steps in the given attachment.
Hope it helps....
Distance travelled in 40s= 40m
Distance travelled in 2mins 20s=
2*60+20= 140s
>>40/40*140= 140m
See the next steps in the given attachment.
Hope it helps....
Attachments:
ksss50094p9j8lr:
very nice answer
and writing too
thanks
yaa
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