Question

A farmer moves along the
boundary of a square field
of side 10m in 40 sec. What will be the magnitude
of displacement of the farmer at the end of 2 min 20 sec?​

Answer 1

Answer:

98,560 m

Explanation:

Initially farmer trave 10m in 40 se

speed = dist/time = 4 m/s^2

now magnitude of displacement at end of 140 sec

S = ut + 0.5 gt ^2

S = 4×140 + 5×140×140

S = 560 + 98,000

S= 98,560 m