Question

. A farmer moves along the boundary of a square field of side 20 m in 80 s. What will be the magnitude of displacement of the farmer at the end of 1 minutes 10 seconds from his initial position?​

Answer 1

Explanation:

His speed = distance/time

= 20/80 = 1/4 m/s

1 min. 10 sec. = 70 sec.

distance covered = 70*(1/4)

= 17.5 m

So displacement= 17.5m as he is moving along a square