A farmer moves along the boundary of a square field of side 10m in 40 s. What will be the magnitude of displacement of the farmar at the end of 2 min 20 sec from his initial position?
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answer is AC is a displacement
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say initial point be A. Side of square field =10m
Time taken to complete one round =40 sec
2 min 20 sec=(60)(2) + 20 sec
Number of rounds in 40 sec = 1
Number of rounds in 140 sec = (1/40)140
. =7/2 rounds
=3 and 1/2
round
In 3 and half rounds farmer will reach at point c
Time taken to complete one round =40 sec
2 min 20 sec=(60)(2) + 20 sec
Number of rounds in 40 sec = 1
Number of rounds in 140 sec = (1/40)140
. =7/2 rounds
=3 and 1/2
round
In 3 and half rounds farmer will reach at point c
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