Question

a farmer moves along the boundary of a square field of side 10 m in 40 seconds what will be the magnitude of displacement of the formal at the end of 2 minutes and 20 seconds

Answer 1

Hii..
Here is your answer..

Solution:-
Distance covered in 40 seconds is 10m
Time taken=2min 20second
$= > 2 \times 60 + 20 \\ = > 120 + 20 \\ = > 140sec$
Total round completed=
$= > \frac{140}{40} \\ = > 3.5round$
Now,as he is moving in square field let its side be ABCD ,he is moving from A to D and here the shortest distance is A to C.Assuming ABC as right angled triangle.We will find Displacement.

For find Distance between A to C ,we will use Pythagorean theorem:-
$= > {(ac)}^{2} = {(ab)}^{2} + {(bc)}^{2}$
$= > {(ac)}^{2} = 100 + 100$

$= > {(ac)}^{2} = {10}^{2} + {10}^{2}$
$= > {(ac)}^{2} = 200 \\ = > {(ac)}^{2} = \sqrt{200} \\ = > ac = 14.14$
Hence,the Displacement will be 14m(approximately)

Hope it helps uh...✌️✌️✌️

Answer 2

The answer is 14.14.......