Question

a farmer moves along the boundary of a square field of side 10 metre in 40 seconds what will be the magnitude of displacement of farmer at end of 2 minutes 20 seconds from his initial position​

Answer 1

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HOPE ITS HELP U

Answer 2

Farmer takes 40 s to move along the boundary. Thus, after 3.5 round farmer will at point C of the field. Thus, after 2 min 20 seconds the displacement of farmer will be equal to 14.14 m north east from initial position.

Given side of square =10m, thus perimeter P=40m

Time taken to cover the boundary of 40 m =40 s

Thus in 1 second, the farmer covers a distance of 1 m

Now distance covered by the farmer in 2 min 20 seconds = 1×140=140m

Now the total number of rotation the farmer makes to cover a distance of 140 meters =perime-tertotal/distance

=3.5