Question

a farmer moves along the boundary of a square field of side 10 m in 40 seconds ? what will be the the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position​

Answer 1

Answer:

Given, the farmer moves along the side of a square field of 10 m in 40 seconds so the farmer completes a total round of the field in 160 seconds

Time given equals 2mins and 20 seconds which equals 140 seconds. Now if the farmer completes a distance of 40m in 160 seconds he will complete a distance of 1m in 4 seconds and hence 1/4 m in 1 second and thus we will cover a distance of 35 m and hence will be just 5 metres away from the starting point

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