Question

A farmer moves along the boundary of a square field of side of size 10 meter reading n 40 second. what will be the magnitude of displacement of the farmer at the end of 2 minute 20 second. of its initial position.

Answer 1

time taken for one side=40sec
distance of one side=10m
so perimeter of square=4s
=4×10=40m
speed= total distance ÷total time =40÷40=1m/sec

so distance covered in 2min 20sec or 140sec = 140÷40=3.5 round

so after a 3 round it will be at its initial position, but it travel .5 m more which is 20m

draw a figure of square field of 10m each side and name them ABCD. draw a diognal from A to c . so in order to find displacement

Ab²=bc²+ca²
Ab²=(10)²+(10)²
Ab ²=200
Ab=√200