A farmer moves along the boundary. of a square field of side 10m is 40s what will be the magnitude of displacement of the farmer at the end of 2min 20s from his initial position?
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1
Answer:
Explanation:
given farmer moves 10x4 m into 40s
= 2min 20s = 60+60+20 = 140s
140/40 = 3.5 x perimeter
= displace = shortest distant from start point = .5 perimeter = 20 meters
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0
Answer:
14.14
Explanation:
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