A farmer moves along the boundary of a square field of side 10 m in 40 s. What will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position?
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A farmer moves along the boundary of a square field of side 10 m in 40 sec What will be magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position?
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Given side of square =10m, thus perimeter P=40m
Time taken to cover the boundary of 40 m =40 s
Thus in 1 second, the farmer covers a distance of 1 m
Now distance covered by the farmer in 2 min 20 seconds = 1×140=140m
Now the total number of rotation the farmer makes to cover a distance of 140 meters =
perimeter
totaldistance
=3.5
At this point, the farmer is at a point say B from the origin O
Thus the displacement s=
10
2
+10
2
from Pythagoras theorem.
s=10
2
=14.14m