Question

a farmer moves along the boundary of a square field of side 10 m in 40 second what will the magnitude of displacement of the farmer at the end of 2 minutes 40 seconds

Answer 1

Total distance 40m in 40 sec.Total time taken by the farmer = 2 min 20 sec. =140 seconds. Total rounds completed= 140/40=3.5 rounds That means if the farmer starts from point A of the square field, he reaches point C.Therefore, displacement is AC. Assume ABC is a right angled triangle. Therefore,AC2= AB2 +BC2  AC2= (10)2 +(10)2 AC2= 100+100 AC2=200 AC = (200)1/2   AC= 10× (2) ½ 

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