A farmer moves along the boundary of a square field of side 10m in 40sec. What will be the magnitude of the displacement of the farmer at the end of 2min 20sec from his initial position
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Total distance 40m in 40 sec.
Total time taken by the farmer = 2 min 20 sec. =140 seconds.
Total rounds completed= 140/40=3.5 rounds
That means if the farmer starts from point A of the square field, he reaches point C.
Therefore, displacement is AC.
Assume ABC is a right angled triangle.
Therefore,
AC2= AB2 +BC2 AC2= (10)2 +(10)2
AC2= 100+100
AC2=200 AC = (200)1/2
AC= 10× (2) ½
✨HOPE THIS ANSWER HELPS YOU✨
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Total time taken by the farmer = 2 min 20 sec. =140 seconds.
Total rounds completed= 140/40=3.5 rounds
That means if the farmer starts from point A of the square field, he reaches point C.
Therefore, displacement is AC.
Assume ABC is a right angled triangle.
Therefore,
AC2= AB2 +BC2 AC2= (10)2 +(10)2
AC2= 100+100
AC2=200 AC = (200)1/2
AC= 10× (2) ½
✨HOPE THIS ANSWER HELPS YOU✨
❤️BE BRAINLY❤️
ilachoudhury8:
Thanks yar for your help
its my pleasure...
But instead of20m in 40sec you wrote 40m in 40 sec. Are there any reason for it or you just made a silly mistake
Sorry not 20m in 40sec it should be 10m in 40 sec Okkkkkk
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