Question

a farmer moves along the boundary of a square field of side 10 metre in 40 seconds what will be the magnitude of displacement of the farmer and the end of 2 minutes 20 seconds from his initial position​

Answer 1

farmer speed 1m per sec

so on 140 sec he will complete 3 raounds and 20m extra

so by pytha. thm

x^2=10^2+10^2

x= 14.14m final displacement from initial position

Answer 2

Answer:

Hi friend, 

Hi friend, Total distance covered 10m in 40sec

Hi friend, Total distance covered 10m in 40secTotal time taken= 2min 20sec= 140sec

Hi friend, Total distance covered 10m in 40secTotal time taken= 2min 20sec= 140secTotal round completed = 140/40=3.5 rounds 

Hi friend, Total distance covered 10m in 40secTotal time taken= 2min 20sec= 140secTotal round completed = 140/40=3.5 rounds So If an object moves from A to D, the shortest path will be from A to C. So displacement is AC, that we will find by phythogoras theorem.

Hi friend, Total distance covered 10m in 40secTotal time taken= 2min 20sec= 140secTotal round completed = 140/40=3.5 rounds So If an object moves from A to D, the shortest path will be from A to C. So displacement is AC, that we will find by phythogoras theorem.AC2= AB2 +BC2 

Hi friend, Total distance covered 10m in 40secTotal time taken= 2min 20sec= 140secTotal round completed = 140/40=3.5 rounds So If an object moves from A to D, the shortest path will be from A to C. So displacement is AC, that we will find by phythogoras theorem.AC2= AB2 +BC2 AC2= (10)2 +(10)2

Hi friend, Total distance covered 10m in 40secTotal time taken= 2min 20sec= 140secTotal round completed = 140/40=3.5 rounds So If an object moves from A to D, the shortest path will be from A to C. So displacement is AC, that we will find by phythogoras theorem.AC2= AB2 +BC2 AC2= (10)2 +(10)2AC2= 100+100

Hi friend, Total distance covered 10m in 40secTotal time taken= 2min 20sec= 140secTotal round completed = 140/40=3.5 rounds So If an object moves from A to D, the shortest path will be from A to C. So displacement is AC, that we will find by phythogoras theorem.AC2= AB2 +BC2 AC2= (10)2 +(10)2AC2= 100+100AC2=200

Hi friend, Total distance covered 10m in 40secTotal time taken= 2min 20sec= 140secTotal round completed = 140/40=3.5 rounds So If an object moves from A to D, the shortest path will be from A to C. So displacement is AC, that we will find by phythogoras theorem.AC2= AB2 +BC2 AC2= (10)2 +(10)2AC2= 100+100AC2=200AC = (200)1/2

Hi friend, Total distance covered 10m in 40secTotal time taken= 2min 20sec= 140secTotal round completed = 140/40=3.5 rounds So If an object moves from A to D, the shortest path will be from A to C. So displacement is AC, that we will find by phythogoras theorem.AC2= AB2 +BC2 AC2= (10)2 +(10)2AC2= 100+100AC2=200AC = (200)1/2 

Hi friend, Total distance covered 10m in 40secTotal time taken= 2min 20sec= 140secTotal round completed = 140/40=3.5 rounds So If an object moves from A to D, the shortest path will be from A to C. So displacement is AC, that we will find by phythogoras theorem.AC2= AB2 +BC2 AC2= (10)2 +(10)2AC2= 100+100AC2=200AC = (200)1/2 AC= 10× (2) ½ 

Hi friend, Total distance covered 10m in 40secTotal time taken= 2min 20sec= 140secTotal round completed = 140/40=3.5 rounds So If an object moves from A to D, the shortest path will be from A to C. So displacement is AC, that we will find by phythogoras theorem.AC2= AB2 +BC2 AC2= (10)2 +(10)2AC2= 100+100AC2=200AC = (200)1/2 AC= 10× (2) ½ Hope it helps......