Question

a farmer moves along the boundary of a square field of side 10 metre in 40 seconds what will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position​

Answer 1

hope it will help you.try to understand the basics.

Answer 2

Answer:

Hi friend, 

Total distance covered 10m in 40sec

Total time taken= 2min 20sec= 140sec

Total round completed = 140/40=3.5 rounds 

So If an object moves from A to D, the shortest path will be from A to C. So displacement is AC, that we will find by phythogoras theorem.

AC2= AB2 +BC2 

AC2= (10)2 +(10)2

AC2= 100+100

AC2=200

AC = (200)1/2

 

AC= 10× (2) ½ 

Hope it helps......