Question

a farmer moves along the boundary of a square field of side 10m in 40s.what will be the magnitude of displacement of the farmer field at the end of 2 min 20sec​

Answer 1

Answer:5m.

Explanation

In 40s,he will cover 10m.so in 4s,he will cover 1m.In 140s,he will cover 35m.displacement=perimeter (40)-35=5m

Answer 2

✯✯ QUESTION ✯✯

A farmer moves along the boundary of a square field of side 10m in 40s.what will be the magnitude of displacement of the farmer field at the end of 2 min 20sec..

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✰✰ ANSWER ✰✰

➮ABCD is a square field of the side 10cm. So , The magnitude of the displacement.

$\implies\tt{{AC}^{2}={AB}^{2}+{BC}^{2}}$

$\implies\tt{AC=\sqrt{{AB}^{2}+{BC}^{2}}}$

➥Here : -

• AB = 10cm
• BC = 10cm

➥Now ,

$\implies\tt{AC=\sqrt{{(10)}^{2}+{(10)}^{2}}}$

$\implies\tt{AC=\sqrt{100+100}}$

$\implies\tt{AC=\sqrt{200}}$

$\implies\tt\bold{AC=10\sqrt{2}m}$