a farmer moves along the boundary of a square field of side 10 m in 40 seconds. what will be the magnitude of displacement of the farmer at the end of 2 minutes 20 second from his initial position?
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Side of a square = 10m.
Perimeter of a square = 4a
= 4 ( 10 )
= 40.
According to the question ,
Total distance covered = 10m in 40seconds.
Total time taken = 2min 20seconds.
= 140seconds.
Total round completed = 140 / 40
=3.5 rounds
In 3 rounds the displacement is zero.
In 0.5 round the farmer reaches the diagonally opposite end of the square from his starting point.
Displacement = AC
= (AB + BC )
= (100+100)
= 10√2 m
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