Question

a farmer moves along the boundary of a square field of side 10 metre in 40 seconds .what will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds
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Answer 1

Answer:

Side of the given square field = 10m

so, perimeter of a square = 4*side = 10 m * 4 = 40 m

Farmer takes 40 s to move along the boundary.

Displacement after 2 minutes 20 s = 2 * 60 s + 20 s = 140 seconds

since in 40 s farmer moves 40 m

Therefore, in 1s the distance covered by farmer = 40 / 40 m = 1m

Therefore, in 140s distance covered by farmer = 1 � 140 m = 140 m. Now, number of rotation to cover 140 along the boundary= Total Distance / Perimeter

= 140 m / 40 m = 3.5 round

Thus, after 3.5 round farmer will at point C of the field.

Answer 2

perimeter of square =4×side=4×10=40 meter

40 meter in 40 seconds ,therefore one meter in one second.

therefore and of two minutes in 20 seconds that is end of 140 sec.

the farmer will cover 140 meter......3.5 rounds.(140/40)

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