Physics, asked by CommanderBrainly, 7 hours ago

A farmer moves along the boundary of a square field of size 10m in 40 s. What will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds?​

Answers

Answered by Ganesh094
1

Given:

  • Side of Square = 10m, thus
  • Perimeter P = 40m
  • Time taken to cover the boundary of 40 m = 40 s
  • Thus in 1 second, the farmer covers a distance of 1 m

⟼ Now distance covered by the farmer in 2 min 20 seconds = 1 × 140 = 140m

⟼ Now the total number of rotation the farmer makes to cover a distance of 140 meters = \frac{Total \:distance}{Perimeter}

= 3.5

⟼ At this point, the farmer is at a point say B from the origin O

⟼ Thus the displacement s = \sqrt{ {10}^{2}  +  {10}^{2} }

⟼ From Pythagoras theorem.

S = 10 \sqrt{2}

° S = 14.14m

Answered by sanoobiyasanu17
1

Explanation:

Farmer takes 40 s to move along the boundary. Thus, after 3.5 round farmer will at point C of the field. Thus, after 2 min 20 seconds the displacement of farmer will be equal to 14.14 m north east from initial position.

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