Physics, asked by daisy777, 1 year ago

a farmer moves along the boundary of a square field of size 10 m in 40 sec. what will be the magnitude of displacement of the farmer at the end of 2 min. and 20 sec. from his initial position.

Answers

Answered by Anonymous
3

hey friend this is your answer

Total distance 40m in 40 sec.

Total time taken by the farmer = 2 min 20 sec. =140 seconds.

Total rounds completed= 140/40=3.5 rounds

That means if the farmer starts from point A of the square field, he reaches point C.

Therefore, displacement is AC.

Assume ABC is a right angled triangle.

Therefore,

AC2= AB2 +BC2  

AC2= (10)2 +(10)2

AC2= 100+100

AC2=200

AC = (200)1/2

 AC= 10× (2) ½

hope it help u mark me

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