Question

A farmer moves along the boundary of a square field offside 5 metre in 30 seconds. What will be the the magnitude of displacement of the farmer at the end of 2 minutes 15 seconds from his initial position

Answer 1

Answer:

Explanation:

Time taken to complete 1round=30s.(it's the time taken to complete the perimeter)

So, 2m.&15sec.s=120+15=135s.

135/30=remainder=15s.

We have to find displacement so at the end of 15sec.s he will be at the diagonally opposite side

Now for taking out the displacement we have to take out the diagonal of the square.

SIDE=5M.,,,

DIAGONAL OF A SQUARE=SIDE*ROOT2=5*ROOT2

ANS..

THANKS & PLS MSRK MY ANS. AS THE BRAINLIEST