Question

a farmer moves along the boundary of a square field size 10 m in 40 second what will be the magnitude of displacement of the former at the end of 2 minute 20 second

Answer 1

if the farmer go 10 m in 40s he will go in 2min 20 s
=1min =60s,=2min =120s +20s =140
if he go 10 m in 40 s
he will go in 140s
=(140÷10)
=14 m answer

Answer 2

hloo frnd and your answer is as follows......

The farmer covers a distance 10m in 40 seconds. It is a square field and all the sides are equal.

By applying unitary method 

In  40 seconds distance covered is 10m

In 140 seconds distance covered will be 10 into 140/40=35m.

Displacement=5m

hope it helps u.. ☺