Question

A farmer moves along the boundary of a square fields of side of side 10m in 40s. What will be the magnitude of displacement of the farmer at the end of 2minutes 20 seconds from its initial position?

Answer 1

Hope it will help you buddy

Answer 2

Explanation= Distance Coverd By The Farmer in 2 Min 20sec it will be written in seconds(2min 20sec)=140 seconds

Total Distance/Perimeter= 140/40=3.5m

The Displacement=

S=√10^2+√10^2                       (Phytagoras Theoram)

S=10√2=14.14