A farmer moves along the boundary of a square filed of side 10m in 40s what will be the magnitude of displacement of the farmer at the end of 2 minutes 20 second from his initial position
Answers
Answer:
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Answer:
The answer, the displacement is 10√2 m
Explanation:
Look, let's note all the given info,
Side of the field = 10m
Time taken to walk along the boundary of the square field = 40s
Time given to calculate the displacement = 2 min 20 s= 2×60 + 20
=140s
Total distance walked by him in 140s =
40s=> 40m
140s => 'x'
Therefore, x = 140×40/40= 140 m
That means, distance covered by him in time 2 min 20s = 140m
Perimeter of the field = 10×4 = 40 m
No. Of rounds taken = 140/40 = 4.5
That means, he didn't complete the 4th time.
Now imagine, make a right angled triangle, from the point the farmer started to the point where he ended ine the second side. Look at the diagram, attached here.
So, it's a right angled triangle,
By Pythagoras theorem,
(Side) ^2 = √(10) ^2 +(10) ^2
Side2 = √100 + 100 =√200
Side = 10√2m ..... ( taking square root of both sides)
{ here side means side of a right angled triangle}
Displacement = final - initial position
= 10√2-0= 10√2m
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