Question

A farmer moves along the boundary of square field of sides 10min. 40sec. What will be the magnitude of displacement of the farmer at the end of 2min. 20sec. from initial position?

Answer 1

distance covered in 40sec= 40m

Answer 2

farmer completes one revolution of square field in 40sec,.so.... no. of revolution completed in 40s=1. no. of revolution completed in 1s=1/40. no of revolution completed in 140s(2min20s)=1/40×140. == 3.5. by pythagorus theorem = hy²=b²+p². hy²=100+100. hy=√200. hy = 14.14m ans.