Question

a farmer moves along the boundary of the square field of side 10 metre in 40 second what will be the magnitude of displacement of the farmer at the end of the 2 minute 20 seconds from his initial position

Answer 1

HEYA!!!
HERE'S YOUR ANSWER!!!
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There could be 2 cases in this problem :-

1st case
When the farmer starts somewhere in the middle.

Time taken to cross 1 side = 40 sec.
Length of side = 10 m
Total Time = 2min 20 sec = 140 sec

Rounds = total time ÷ time taken to cross 1 side

= 140/40
= 3.5 rounds
=> Displacement is equal to Lenght to side as it is a square
Therefore Displacement = 10m.
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2nd case
If he starts from edge.

Distance travelled will be same as case 1 as time is same.
Therefore Displacement = Hypotunese
= h^2 = p^2 + b^ 2
= h^2 = 100 + 100

= h^2 = 200
$h = \sqrt{200}$
h = 14.142 mts.
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please look at attached fig.
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HOPE IT HELPED!!!

Answer 2

Answer:

Hi friend, 

Hi friend, Total distance covered 10m in 40sec

Hi friend, Total distance covered 10m in 40secTotal time taken= 2min 20sec= 140sec

Hi friend, Total distance covered 10m in 40secTotal time taken= 2min 20sec= 140secTotal round completed = 140/40=3.5 rounds 

Hi friend, Total distance covered 10m in 40secTotal time taken= 2min 20sec= 140secTotal round completed = 140/40=3.5 rounds So If an object moves from A to D, the shortest path will be from A to C. So displacement is AC, that we will find by phythogoras theorem.

Hi friend, Total distance covered 10m in 40secTotal time taken= 2min 20sec= 140secTotal round completed = 140/40=3.5 rounds So If an object moves from A to D, the shortest path will be from A to C. So displacement is AC, that we will find by phythogoras theorem.AC2= AB2 +BC2 

Hi friend, Total distance covered 10m in 40secTotal time taken= 2min 20sec= 140secTotal round completed = 140/40=3.5 rounds So If an object moves from A to D, the shortest path will be from A to C. So displacement is AC, that we will find by phythogoras theorem.AC2= AB2 +BC2 AC2= (10)2 +(10)2

Hi friend, Total distance covered 10m in 40secTotal time taken= 2min 20sec= 140secTotal round completed = 140/40=3.5 rounds So If an object moves from A to D, the shortest path will be from A to C. So displacement is AC, that we will find by phythogoras theorem.AC2= AB2 +BC2 AC2= (10)2 +(10)2AC2= 100+100

Hi friend, Total distance covered 10m in 40secTotal time taken= 2min 20sec= 140secTotal round completed = 140/40=3.5 rounds So If an object moves from A to D, the shortest path will be from A to C. So displacement is AC, that we will find by phythogoras theorem.AC2= AB2 +BC2 AC2= (10)2 +(10)2AC2= 100+100AC2=200

Hi friend, Total distance covered 10m in 40secTotal time taken= 2min 20sec= 140secTotal round completed = 140/40=3.5 rounds So If an object moves from A to D, the shortest path will be from A to C. So displacement is AC, that we will find by phythogoras theorem.AC2= AB2 +BC2 AC2= (10)2 +(10)2AC2= 100+100AC2=200AC = (200)1/2

Hi friend, Total distance covered 10m in 40secTotal time taken= 2min 20sec= 140secTotal round completed = 140/40=3.5 rounds So If an object moves from A to D, the shortest path will be from A to C. So displacement is AC, that we will find by phythogoras theorem.AC2= AB2 +BC2 AC2= (10)2 +(10)2AC2= 100+100AC2=200AC = (200)1/2 

Hi friend, Total distance covered 10m in 40secTotal time taken= 2min 20sec= 140secTotal round completed = 140/40=3.5 rounds So If an object moves from A to D, the shortest path will be from A to C. So displacement is AC, that we will find by phythogoras theorem.AC2= AB2 +BC2 AC2= (10)2 +(10)2AC2= 100+100AC2=200AC = (200)1/2 AC= 10× (2) ½ 

Hi friend, Total distance covered 10m in 40secTotal time taken= 2min 20sec= 140secTotal round completed = 140/40=3.5 rounds So If an object moves from A to D, the shortest path will be from A to C. So displacement is AC, that we will find by phythogoras theorem.AC2= AB2 +BC2 AC2= (10)2 +(10)2AC2= 100+100AC2=200AC = (200)1/2 AC= 10× (2) ½ Hope it helps......