Physics, asked by Jiyaa021, 7 months ago

. A FARMER MOVES ALONG THE BOUNDARY OF THE SQUARE FIELD OF SIDE 20m IN 40 seconds . WHAT WILL BE THE MAGNITUDE OF THE DISPLACEMENT OF THE FARMER AT THE END OF 3 minutes FROM ITS INITIAL POSITION ? *
1 point
28.28 m
14.14 m
17.07 m
35.35 m

Answers

Answered by Anonymous
2

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Farmer takes 40 s to move along the boundary. Thus, after 3.5 round farmer will at point C of the field. Thus, after 2 min 20 seconds the displacement of farmer will be equal to 14.14 m north east from initial position.

hope it helps

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