Question

a farmer moves along the boundary of the square field of side 10 metre in 40 seconds what will be the magnitude of the displacement of the form at the end of 2 minutes 20 seconds from his initial position​

Answer 1

Answer:



Here, Side of the given square field = 10m

so, perimeter of a square = 4*side = 10 m * 4 = 40 m

Farmer takes 40 s to move along the boundary.

Displacement after 2 minutes 20 s = 2 * 60 s + 20 s = 140 seconds

since in 40 s farmer moves 40 m

Therefore, in 1s the distance covered by farmer = 40 / 40 m = 1m

Therefore, in 140s distance covered by farmer = 1 � 140 m = 140 m. Now, number of rotation to cover 140 along the boundary= Total Distance / Perimeter

= 140 m / 40 m = 3.5 round

Thus, after 3.5 round farmer will at point C of the field.



Thus, after 2 min 20 seconds the displacement of farmer will be equal to 14.14 m north east from initial position.