Question

A farmer moves along the boundry of square
feet of side 10m in 40s. What will be the
magnitude of displacement of the farmer at the
end of 2min 20s from his initial position?​

Answer 1

Answer:

Side of the square = 10 m

Perimeter of the square = 4*10 = 40 m

He completes 1 round in 40 s.

So, speed = 40/40 = 1 m/s

So, distance covered in 2 min 20 s or 140 s is = 140 * 1 = 140 m

Number of rounds of the square completed in moving through 140 m is = 140/40 = 3.5

In 3 rounds the displacement is zero. In 0.5 round the farmer reaches the diagonally opposite end of the square from his starting point.

Displacement = AC = (AB2 + BC2)1/2 = (100+100)1/2 = 10√ 2 m

Answer 2

Answer:

i hope you will understand....